4.9t^2-9t=6

Solution for 4.9t^2-9t=6 equation:

4.9t^2-9t=6

We move all terms to the left:

4.9t^2-9t-(6)=0

a = 4.9; b = -9; c = -6;
Δ = b2-4ac
Δ = -92-4·4.9·(-6)
Δ = 198.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{198.6}}{2*4.9}=\frac{9-\sqrt{198.6}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{198.6}}{2*4.9}=\frac{9+\sqrt{198.6}}{9.8}
$